How to calculate the speed of fall
How to calculate the speed of fall
A drop is called the motion of a body in a gravitationalfield of the Earth. Its peculiarity is that it always takes place with a constant acceleration, which is g≈9.81 m / s². This should be taken into account when the object is thrown horizontally.
You will need
- - range finder;
- - electronic stopwatch;
- - calculator.
Instructions
1
If the body falls freely from a certain height h, measure it with a range finder or any other device. Calculate speed falls body v, finding the square root of the product of the acceleration of free falls to the height and the number 2, v = √ (2 ∙ g ∙ h). If the body already had speed v0, then to the resulting result, add its value v = √ (2 ∙ g ∙ h) + v0.
2
Example. The body freely falls from a height of 4 m at zero initial speed. What will be his speed when you reach the earth's surface? Calculate speed falls body by the formula, taking into account that v0 = 0. Make the substitution v = √ (2 ∙ 9.81 ∙ 4) ≈8.86 m / s.
3
Measure the time falls body t electronic stopwatch in seconds. Find it speed at the end of a period of time, which continued the movement by adding to the initial velocity v0 the product of time for the acceleration of free falls v = v0 + g ∙ t.
4
Example. The stone began to fall from the initial speed1 m / s. Find it speed in 2 seconds. Substitute the values of the indicated values in the formula v = 1 + 9.81 ∙ 2 = 20.62 m / s.
5
Calculate speed falls body, thrown horizontally. In this case, its movement is the result of two types of movement, in which the body participates simultaneously. This uniform movement horizontally and uniformly accelerated - along the vertical. As a result, the trajectory of the body has the form of a parabola. The velocity of the body at any time will be equal to the vector sum of the horizontal and vertical velocity components. Since the angle between the vectors of these velocities is always straight, to determine the velocity falls body, thrown horizontally, usetheorem of Pythagoras. The speed of the body will be equal to the square root of the sum of the squares of the horizontal and vertical components at a given time v = √ (v mountains² + v ver²). The vertical component of the speed is calculated by the method described in the previous paragraphs.
6
Example. The body is thrown horizontally from a height of 6 m speed4 m / s. Define it speed when striking the ground. Find the vertical component of the velocity when striking the ground. It will be the same as if the body fell freely from a given height v vert = √ (2 ∙ g ∙ h). Substitute the value in the formula and get v = √ (v mountains² + 2 ∙ g ∙ h) = √ (16 + 2 ∙ 9.81 ∙ 6) ≈ 11.56 m / s.