Tip 1: How to solve the discriminant
Tip 1: How to solve the discriminant
The solution of the quadratic equation is often reduced to finding discriminant. From its value depends on whether the equation has roots and how much it will be. Work around the search discriminant can only be done by the Viet formula theorem if the quadratic equation is reduced, that is, has a unit coefficient with the highest factor.
Instructions
1
Determine whether your equation is square. Such it will be, if it looks like: ax ^ 2 + bx + c = 0. Here a, b and c are numerical constant factors, and x is a variable. If the unit term is in the higher term (that is, the volume with the higher power, hence this is x ^ 2), then we can not look for the discriminant and find the roots of the equation by Viet's theorem, which says that the solution is the following: x1 + x2 = - b; x1 * x2 = c, where x1 and x2 are the roots of the equation, respectively. For example, the reduced quadratic equation: x ^ 2 + sx + 6 = 0. By Viet's theorem, a system of equations is obtained: x1 + x2 = -5; x1 * x2 = 6 . Thus, we obtain x1 = -2; x2 = -3.
2
If the equation is not reduced, then searches discriminant not to be avoided. Determine it by the formula: D = b ^ 2-4as. If the discriminant is less than zero, then the quadratic equation has no solutions, if the discriminant is zero, then the roots coincide, that is, the quadratic equation has only one solution. And only if the discriminant is strictly positive, the equation has two roots.
3
For example, the quadratic equation: 3x ^ 2-18x + 24 = 0.With the highest term there is a factor that is different from unity, hence, it is necessary to find the discriminant: D = 18 ^ 2-4 * 3 * 24 = 36. The discriminant is positive, therefore, the equation has two roots. X1 = (-b) + vD) / 2a = (18 + 6) / 6 = 4; x2 = (-b) -vD) / 2a = (18-6) / 6 = 2.
4
Complicate the problem by taking the following expression: 3x2 + 9 = 12x-x2. Carry all the terms to the left side of the equation, remembering to change the sign of the coefficients, and leave zero on the right-hand side: 3x ^ 2 + x ^ 2-12x + 9 = 0; 4x ^ 2 -12x + 9 = 0. Now, looking at this expression, we can say that it is square. Find the discriminant: D = (-12) ^ 2-4 * 4 * 9 = 144-144 = 0. The discriminant is zero, so this quadratic equation has only one root, which is determined by the simplified formula: x1,2 = -v / 2a = 12/8 = 3/2 = 1,5.
Tip 2: How to calculate the discriminant
To solve the quadratic equation, you must first determine its discriminant. Determined discriminant, we can immediately conclude about the number of roots of the quadratic equation. In the general case, to solve a polynomial of any order higher than the second, it is also necessary to look for discriminant.
You will need
- mathematical operations
Instructions
1
Suppose you have a quadratic equation reduced to the form a (x * x) + b * x + c = 0. Its discriminant will be denoted by the letter D and will be equal to D = (b * b) -4ac.
2
The discriminant of the quadratic equation can be greater than zero, zero or less than zero. If it is greater than zero, then the equation has two real roots. If discriminant is equal to zero, then the equation has one real root. If discriminant is less than zero, then the equation has no realroots, but has two complex roots. The roots of the quadratic equation will be found by the formulas: x1 = (-b + sqrt (D)) / 2a, x2 = (-b-sqrt (D)) / 2a (in the case of real roots).
3
If the quadratic equation can be represented as a (x * x) + 2 * b * x + c = 0, then it is simpler to find the abbreviated discriminant of this equation in the form: D = (b * b) -ac. With such discriminantthe roots of the equation will look like this: x1 = (-b + sqrt (D)) / a, x2 = (-b-sqrt (D)) / a.
Tip 3: Square equations and how to solve them
A quadratic equation is a special kind of algebraicequation, whose name is due to the presence in it of a square term. Despite the seeming complexity, such equations have a clear algorithm for solving.
Equation that is squarea trinomial, is usually called a quadratic equation. From the point of view of algebra, it is described by the formula a * x ^ 2 + b * x + c = 0. In this formula, x is the unknown, which is to be found (it is called a free variable); a, b and c are numerical coefficients. There are a number of limitations with respect to the components of this formula: thus, the coefficient a must not be equal to 0.